Calculating Net Force: 930kg Car & 320kg Trailer with 2.16 m/s2 Acceleration

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Homework Help Overview

The problem involves a 930 kg car pulling a 320 kg trailer with an acceleration of 2.16 m/s², focusing on determining the net force acting on the car while ignoring frictional forces.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the car and trailer system, with some suggesting to consider the system as a whole while others emphasize the individual forces on the car. There is confusion regarding the role of the trailer's mass in calculating the net force on the car.

Discussion Status

Multiple interpretations of the problem are being explored, with participants offering different perspectives on how to account for the forces involved. Some guidance has been provided, but no consensus has been reached regarding the correct approach to find the net force on the car.

Contextual Notes

Participants are navigating assumptions about the forces acting on the car and trailer, particularly regarding the effects of the trailer's mass and the nature of action-reaction pairs in this context.

frosti
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Homework Statement


A 930 kg car is pulling a 320 kg trailer. Together the car and trailer move forward with an acceleration of 2.16 m/s2. Ignore any frictional force of air drag on the car and all frictional forces on the trailer. determine the net force on the car.


Homework Equations


f = ma


The Attempt at a Solution


I thought the forces that are acting on the car is a force moving car forward and a force applied by the trailer slowing the car down so the net force on the car should be 930 x 2.16 - 320 x 2.16 = 1317.6. However, it is wrong. I don't really know how to think about this problem, can anyone please provide me with some insight?
 
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I believe you're over thinking this one. The problem clearly states to ignore any frictional force of air drag or frictional forces of the trailer. Therefore, thinking about the system as a whole, the net force would simply equal the mass of the system as a whole times the acceleration of the system.

F=ma
 
jenglish is wrong, frosti is getting there, kind of: there is one friction force pushing the car forward, and a force exerted by the trailer on the car, backward. But there is also a force on the trailer forward. Draw a pucture with these 3 forces, and you 'll find the answer.
 
borgwal said:
jenglish is wrong, frosti is getting there, kind of: there is one friction force pushing the car forward, and a force exerted by the trailer on the car, backward. But there is also a force on the trailer forward. Draw a pucture with these 3 forces, and you 'll find the answer.

those two "extra" forces you mentioned are the tension on the connecting cable...they should ultimately cancel
 
jenglish said:
those two "extra" forces you mentioned are the tension on the connecting cable...they should ultimately cancel

No: the question is about the net force on the car, which includes the force the trailer (or the connecting cable if you wish) exerts. The net force on the car is not equal to "the mass of the system times the acceleration of the system": the latter quantity would be the net force on the system of car + trailer, not the net force on the car.

In any case, the question is simple, but not in that way.
 
Last edited:
thank you for your reply guys.

borgwal, don't force exerted by the trailer on the car backward and the force on the trailer forward on the car cancel out? so all that left me is one force 930 x 2.16?

jenglish, you are saying the net force should be (930 + 320) x 2.16 right? but why would the net force on the car also include mass of the trailer?

I'm confused here on which one sounds more right. Could you guys elaborate a bit more?
 
frosti said:
thank you for your reply guys.

borgwal, don't force exerted by the trailer on the car backward and the force on the trailer forward on the car cancel out? so all that left me is one force 930 x 2.16?

jenglish, you are saying the net force should be (930 + 320) x 2.16 right? but why would the net force on the car also include mass of the trailer?

I'm confused here on which one sounds more right. Could you guys elaborate a bit more?

Yes, the net force on the car is simply 930 x 2.16 9 (it's simple after all). There is no force the trailer exerts on the car in the forward direction, only one in the backward direction. Since the net force on the total system [a friction force on the car, in the forward direction] is (930+320) x 2.16 it means the trailer is pulling back the car with a force 320 x 2.16, and the car is pulling the trailer forward with that same force in the opposite direction [its an action-reaction pair]. If you draw all the forces it will be clearer, I suppose.
 
I suppose I didn't read this question thoroughly enough, assuming it was asking for the force on the system
 
By the way: the action-reaction pair of forces cancels out only when the car and trailer are seen as 1 system. When considering the car by itself there is no such cancellation.
 
  • #10
thank you guys so much. I got it now.
 

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