Calculating No-Load Voltage for DC Generator

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The discussion revolves around calculating the no-load voltage of a DC generator rated at 16 kW, 250 V, and 64 A at 1000 rpm. The user is confused about why the no-load voltage is expected to be 2400 V, which exceeds the rated voltage of 250 V. It is suggested that the discrepancy may be due to the internal resistance of the generator not being considered in the rated voltage. The user seeks clarification on how to approach solving this problem, indicating a need for understanding the relationship between no-load conditions and internal resistance. The conversation highlights the importance of recognizing how internal factors affect voltage readings in generators.
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Homework Statement



The ratings of a dc generator are given (16 kW, 250 V, and 64 A) when it rotates at 1000 rpm. Then the question asks to find the no-load voltage at 1000 rpm when there isn't a circuit hooked up to the generator.

Homework Equations



P = IV
V = IR
Kirchhoff's circuit rules
\omega = 2(\pi)(f)

The Attempt at a Solution



I know the answer is suppose to be 2400 V, but I have no idea why the no-load voltage is greater than 250 V.
 
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I thought that the no-load voltage would be equal to the rated voltage because there isn't a circuit attached, but clearly that isn't the case. Can someone explain why this is so? Is it because the generator has an internal resistance that's not being accounted for in the rated voltage? If so, how would I go about solving this problem? Thanks.
 

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