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## Homework Statement

The attached figure shows a simple voltage-divier connecting a dc voltage source to a variable resistive load. Design the voltage divider to provide a voltage of about 5V (+/- 10%) across the variable load. The load-current demand varies in the range of 0 to 5mA, and the available dc-supply voltage is 15V.

## Homework Equations

V=IR

equivalent resistance across parallel circuits: R1*R2/(R1+R2)

equivalent resistance across the series circuit: R1+R2

## The Attempt at a Solution

I understand that the voltage across the Load is 5V, which would mean that the voltage across the R2 resistor is also 5V. This would mean that the voltage drop across R1 is 10V since KVL states the sum of voltages across a loop must be zero. I also know that the voltage divider rule states that the voltage across V(R2)=15*(R2/R1+R2).

I am not sure how to move forward from here. Please help