DC generator question -- what is happening at no load?

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Discussion Overview

The discussion revolves around the behavior of a DC generator under no load conditions, specifically addressing the relationship between voltage, armature current, and resistance. Participants explore the implications of the equation V=E–IaRa in the context of no load operation.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants question why the equation V=E–IaRa simplifies to V=E at no load, seeking clarification on the role of armature current and resistance.
  • Others propose that at no load, the armature current (Ia) approaches zero, leading to the resistance term becoming negligible.
  • A participant challenges the initial question by asking for the value of V when Ia=0, suggesting a need for clearer understanding of the equation.
  • One participant emphasizes the importance of aligning mathematical expressions with physical concepts, noting that multiplication by zero results in zero, which supports the argument that resistance does not affect voltage at no load.
  • Another participant confirms the reasoning behind disregarding resistance at no load, indicating agreement with the insights shared.

Areas of Agreement / Disagreement

While there is some agreement on the reasoning behind the behavior of the DC generator at no load, the discussion includes differing interpretations and clarifications regarding the implications of the equation and the concept of no load.

Contextual Notes

Participants express varying levels of understanding regarding the mathematical relationships involved, and there are unresolved questions about the implications of these relationships in practical scenarios.

Who May Find This Useful

This discussion may be useful for students and practitioners interested in electrical engineering, particularly those studying the principles of DC generators and their operational characteristics.

dave pallamino
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In the case of a d.c. generator, if V=E–IaRa when current flows through the armature, why does V = E at no load?
Why does the resistance element become disregarded at no load? Is this because the resistance can't cause the voltage to drop at no load?
 
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How is the armature current related to the load current? What can you say about the armature current under no load condition?

If you are having a hard time visualizing "no load". Then imagine a resistance load and you start increasing the resistance. When you get to the order of a Megohm (like what a voltmeter may have), how much current is through the armature, and what is the votage approaching?
 
dave pallamino said:
In the case of a d.c. generator, if V=E–IaRa when current flows through the armature, why does V = E at no load?

Your question makes no sense. In that equation, what is the value of V when Ia=0?
 
dave pallamino said:
V=E–IaRa

Have you taken first year algebra ?

dave pallamino said:
Why does the resistance element become disregarded at no load?

Is multiplication by zero 'disregarded" ?

dave pallamino said:
Is this because the resistance can't cause the voltage to drop at no load?
Bravo !
Most anything when multiplied by zero yields a zero result.
:smile:

Always make your words and your math come into agreement.
It's important to form that habit because
our minds will believe word constructs that are physically impossible
and that's why they call math "the language of science" .
:oldwink:
old jim
 
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dave pallamino said:
Why does the resistance element become disregarded at no load? Is this because the resistance can't cause the voltage to drop at no load?
Yes!
Correct!
You got it!
Good insight!

Carry on with your studies, you passed the first exam.

Cheers,
Tom
 
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