How Do I Calculate Normal Force for a Wooden Block?

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To calculate the normal force for a rectangular wooden block, recognize that the normal force equals the weight of the block when it rests on a horizontal surface. Since the weight of the block is 2N, the normal force is also 2N. The formula for kinetic friction is the force of friction equals the coefficient of friction multiplied by the normal force. There is no need to multiply the weight by 9.81 m/s², as the weight is already expressed in Newtons. Understanding this relationship allows for accurate calculations of frictional forces.
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Hello there,

I am trying to find the coefficient of friction for a rectangular wooden block. I have the force of friction but I do not know how to find the normal force.

The weight of 1 block is 2N. Could someone please explain how I could find the normal force? Would I just multiply 2N by 9.81 m/s^2 ?

Thanks!
 
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The formula typically used for this scenario is (The Force of Kinetic Friction) = (The Coefficient of Friction) * (The Normal Force)

For the weight of the block, you should realize that both weight and force are the same units. For an object resting on a horizontal surface the normal force and weight must cancel out, otherwise the object would be accelerating up or down.

You should be able to figure out the rest.

By the way, these forums have sone guidelines about where to post: https://www.physicsforums.com/showthread.php?t=8128
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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