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Calculating Number of Moles & Ions in CaCI2
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[QUOTE="rachelmaddiee, post: 6281167, member: 671496"] [B]Homework Statement:[/B] I have a question [B]Relevant Equations:[/B] N/A Here is my work** Can someone please tell me if this is correct? mass = 27.8 g CaCI2 Number of CaCI2 in the compound = (unknown) Number of CI- ions in the compound = (unknown) Number of moles = mass/molar mass To find the number of moles of CaCI2 first you find the molar mass of the compound. 1 mole Ca x 40.08 g Ca/1 mole Ca = 40.08 g 1 mole CI x 30.45 g CI/1 mole CI = 30.45 g 1 mole CI x 30.45 g CI/1 mole CI = 30.45 g molar mass = (40.08 g + 35.45 g + 35.45 g) = 110.98 g/mol CaCI2 27.8 g CaCI2 x 1 mol CaCI2/110.98 g CaCI2 = 0.250 mol CaCI2 Now from equation No of Chloride ions are : 6.02 x 10^23 x 2 CI- ions = 1.204 x 10^23 CI- ions [ATTACH type="full"]255067[/ATTACH] [/QUOTE]
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Calculating Number of Moles & Ions in CaCI2
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