Calculating Peak Current in an LRC Series Circuit

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SUMMARY

The discussion focuses on calculating the peak current in an LRC series circuit with specific parameters: resistance (R) of 200Ω, inductance (L) of 32mH, capacitance (C) of 2.5μF, a peak voltage (V0) of 200V, and a frequency (f) of 770Hz. The relevant equations include Ohm's Law (V = IR) and the differential equation for the circuit (-L dI/dT + Q/C = 0). The relationship between peak current and peak voltage in an AC circuit is established through the impedance, which is derived from these parameters.

PREREQUISITES
  • Understanding of LRC circuit components: resistance, inductance, and capacitance.
  • Familiarity with AC circuit analysis and impedance calculations.
  • Knowledge of differential equations as applied to electrical circuits.
  • Proficiency in using Ohm's Law in both AC and DC contexts.
NEXT STEPS
  • Learn how to calculate impedance in LRC circuits.
  • Study the concept of phasors in AC circuit analysis.
  • Explore the application of Kirchhoff's laws in AC circuits.
  • Investigate the effects of varying frequency on peak current in LRC circuits.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or designing LRC circuits in AC applications.

bgav88
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Homework Statement



An LRC series circuit with R = 200!, L = 32mH, and C = 2.5μF is
powered by an ac voltage source of peak voltageV0 = 200V and frequency
f = 770Hz. Determine the peak current that flows in this circuit.


Homework Equations



V= IR

-L dI/dT +Q/C = 0

w = 2 pi f

The Attempt at a Solution



-.032 H- IR+ Q/c = 0
 
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Hi bgav88,

bgav88 said:

Homework Statement



An LRC series circuit with R = 200!, L = 32mH, and C = 2.5μF is
powered by an ac voltage source of peak voltageV0 = 200V and frequency
f = 770Hz. Determine the peak current that flows in this circuit.


Homework Equations



V= IR

-L dI/dT +Q/C = 0

w = 2 pi f

What's the relationship between peak current and peak voltage for an AC circuit?

(For a DC circuit you would use Ohm's law; what similar equation applies here?)
 

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