Calculating Peak-to-Peak Amplitude of Out-of-Phase Sine Waves

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SUMMARY

The discussion centers on calculating the peak-to-peak amplitude of two out-of-phase sine waves, each with a peak-to-peak amplitude of 81. When these waves are 90 degrees out of phase, the resultant wave's peak-to-peak amplitude is determined by analyzing their intersection points. The specific sine functions involved are 40.5sin(ωt) and 40.5sin(ωt - π/2), leading to a resultant amplitude of 81, as the waves do not interfere constructively or destructively due to their phase difference.

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  • Understanding of sine wave properties and phase differences
  • Familiarity with trigonometric functions and their graphical representations
  • Knowledge of amplitude and its significance in wave mechanics
  • Basic skills in graphing functions and interpreting intersection points
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  • Study the principles of wave interference and superposition
  • Learn about phase shifts in trigonometric functions
  • Explore graphical methods for analyzing wave interactions
  • Investigate the mathematical derivation of resultant amplitudes in wave mechanics
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Two sine waves have equal peak to peak amplitudes 81 but are out of phase by 90 degrees. What is the peak to peak amplitude of the resultant wave.


I have no idea how to start this question, could someone give me guidance?
 
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Graph
40.5sin(\omega t-\frac{\pi}{2}) and 40.5sin(\omega t)
The points on the graph where these functions intersect are where the resultant will have its maximum (and minimum) amplitudes.
 

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