Phase difference between the two waves

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SUMMARY

The discussion focuses on calculating the resultant peak-to-peak amplitude of two sine waves based on their phase differences. For two waves with equal peak-to-peak amplitudes of 89 and a phase difference of 180 degrees, the resultant amplitude is 0. In the case of two waves with equal amplitudes of 81 and a phase difference of 90 degrees, the resultant amplitude is approximately 81√2. Additionally, the phase difference for light traveling different paths is calculated using the path lengths of 10.29600 mm and 10.29765 mm, resulting in a phase difference of approximately 0.025 radians.

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Sloan650
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1) Two sine waves have equal peak to peak amplitudes 89 but are out of phase by 180 degrees. What is the peak to peak amplitude of the resultant wave.

2)Two sine waves have equal peak to peak amplitudes 81 but are out of phase by 90 degrees. What is the peak to peak amplitude of the resultant wave.

3) Light from a single source goes from O to X via two paths: directly OX, path length 10.29600 mm and indirectly OYX, path length 10.29765 mm. The wavelength is 660 nm. What is the phase difference between the two waves when they meet at X.
 
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Hello Sloan650, welcome to PF! Maybe you didn't get a chance to read the forum rules. The thing you need to do is show what work you have done. If you have done very little, the odds of getting any help are low. If you show a sincere effort, your stock will rise. Give the problems a try! :smile:
 

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