# Calculating period of a function

1. Oct 30, 2009

### andrey21

Hi ive been given this question for cooursework and am really struggling, help needed!
heres the question:

What is the period of the function?
f(t) = 3t 0≤t≤π, where f(t)=f(t+1)

2. Relevant equations

3. The attempt at a solution

2. Oct 30, 2009

### aPhilosopher

What are you struggling with? Do you know what it means for a function to be periodic?

3. Oct 30, 2009

### andrey21

yes i understand what it means to be periodic, is the period of the function 1

4. Oct 30, 2009

### aPhilosopher

what's the definition of periodicity that you've been given?

5. Oct 30, 2009

### LCKurtz

"What is the period of the function?
f(t) = 3t 0≤t≤π, where f(t)=f(t+1)"

This looks contradictory to me. f(1) = 3, f(2) = 6 contradicts f(t)=f(t+1) when t = 1. You can't have both.

6. Oct 30, 2009

### aPhilosopher

3t is only specified as the value of f on the interval [0, n] where n is the period of f.

7. Oct 30, 2009

### LCKurtz

0≤t≤π looks like pi to me from the copy and paste list: π. Doesn't look like 0 ≤ t ≤ n.

Perhaps it was just a typo.

8. Oct 30, 2009

### aPhilosopher

Now that you put them next to each other, it does look like pi. I don't think that the function is periodic of period 1 either in that case.