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Calculating period of a function

  1. Oct 30, 2009 #1
    Hi ive been given this question for cooursework and am really struggling, help needed!
    heres the question:

    What is the period of the function?
    f(t) = 3t 0≤t≤π, where f(t)=f(t+1)



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 30, 2009 #2
    What are you struggling with? Do you know what it means for a function to be periodic?
     
  4. Oct 30, 2009 #3
    yes i understand what it means to be periodic, is the period of the function 1
     
  5. Oct 30, 2009 #4
    what's the definition of periodicity that you've been given?
     
  6. Oct 30, 2009 #5

    LCKurtz

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    "What is the period of the function?
    f(t) = 3t 0≤t≤π, where f(t)=f(t+1)"

    This looks contradictory to me. f(1) = 3, f(2) = 6 contradicts f(t)=f(t+1) when t = 1. You can't have both.
     
  7. Oct 30, 2009 #6
    3t is only specified as the value of f on the interval [0, n] where n is the period of f.
     
  8. Oct 30, 2009 #7

    LCKurtz

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    0≤t≤π looks like pi to me from the copy and paste list: π. Doesn't look like 0 ≤ t ≤ n.

    Perhaps it was just a typo.
     
  9. Oct 30, 2009 #8
    Now that you put them next to each other, it does look like pi. I don't think that the function is periodic of period 1 either in that case.
     
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