Calculating period of a function

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Homework Help Overview

The problem involves determining the period of a function defined as f(t) = 3t over the interval 0≤t≤π, with a condition that f(t)=f(t+1). Participants are exploring the implications of periodicity in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss their understanding of periodic functions and question the definition of periodicity provided. There is a focus on the apparent contradiction in the function's definition and the conditions given.

Discussion Status

The discussion is active, with participants raising questions about the function's periodicity and the implications of the provided conditions. Some participants suggest that the function may not be periodic as initially thought, and there is an exploration of potential typographical errors in the problem statement.

Contextual Notes

There is uncertainty regarding the correct interpretation of the function's definition and the specified interval, with participants noting possible contradictions in the conditions provided.

andrey21
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Hi I've been given this question for cooursework and am really struggling, help needed!
heres the question:

What is the period of the function?
f(t) = 3t 0≤t≤π, where f(t)=f(t+1)



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The Attempt at a Solution

 
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What are you struggling with? Do you know what it means for a function to be periodic?
 
yes i understand what it means to be periodic, is the period of the function 1
 
what's the definition of periodicity that you've been given?
 
"What is the period of the function?
f(t) = 3t 0≤t≤π, where f(t)=f(t+1)"

This looks contradictory to me. f(1) = 3, f(2) = 6 contradicts f(t)=f(t+1) when t = 1. You can't have both.
 
3t is only specified as the value of f on the interval [0, n] where n is the period of f.
 
0≤t≤π looks like pi to me from the copy and paste list: π. Doesn't look like 0 ≤ t ≤ n.

Perhaps it was just a typo.
 
Now that you put them next to each other, it does look like pi. I don't think that the function is periodic of period 1 either in that case.
 

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