Calculating Plane Height When Stone is Thrown at It

[siddharthmishra19]

Q: A plane is flying horizontal to the ground with uniform velocity Vo. A stone is thrown at it with velocity V1 and angle alpha to the horizontal. If the stone hit the plane, at what height is it flying?

The simple equations of uniform acceleration are available to me.

We obviously have to equate

x coordinate of plane during collision = x cooridinate of stone during collision
y coordinate of plane during collision = y coordinate of ston during collision.

I have attached an image of how I percieve this question. Sorry for the crappy drawing.

Anyway, my question is how to write the equations of motion for the plane and stone. Thank you.

 

[Astronuc]

Determine the initial vertical velocity of the stone, then relate the height it achieves in terms of initial velocity and constant acceleration (or deceleration) due to gravity.

http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html

The stone has to achieve the same altitude, then it has to be at that altitude at the same time.

Basically, the problem is one of intersecting curves/trajectories.

 

[siddharthmishra19]

But it doesn't hit the plane at its maximum height. Or am I missing something?

 

[Doc Al]

Q: A plane is flying horizontal to the ground with uniform velocity Vo. A stone is thrown at it with velocity V1 and angle alpha to the horizontal. If the stone hit the plane, at what height is it flying?

Are we to assume that the stone is thrown at the instant that the plane passes directly overhead? If so, take advantage of that information.

 

[asrafally]

you should use the equation S= ut +1/2 at^2
or in this case S= ut - 1/2 gt^2
v^2=u^2 + 2as
I sincerely believe there are some information missing