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(Very Basic) Movement of Charged Particles Through Parallel Plate Apparatus

  1. Jan 27, 2013 #1
    1. The problem statement, all variables and given/known data
    What is the electric potential two-fifths of the way through a parallel-plate apparatus (from the positive plate) if the plates have a total separation of 5cm and field strength of 5000N/C.


    2. Relevant equations
    Difference Potential Energy = Electric Field Strength x Distance
    V = ed

    3. The attempt at a solution
    = 5000 x (0.05 - ((2/5)(0.05))
    = 5000 x (0.05-0.02)
    = 5000 x (0.03)
    = 150

    Real answer is 250, so basically the whole distance of 0.05.
    I thought that electric potential decreases as the current flows from positive to negative?
    That is why, in my solution, I took the two-fifth of the whole distance away.
    Edit: Please let me know if my solution as infact correct :)
     
    Last edited: Jan 27, 2013
  2. jcsd
  3. Jan 27, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    Your solution looks fine to me. As you say, the total potential difference is 250V, so a correct answer for the potential partway between the plates can't be 250V also.
     
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