Calculating Potential Energy of Deuterium

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SUMMARY

The discussion focuses on calculating the potential energies associated with deuterium, which consists of one proton and one neutron. The binding energy of deuterium is established at 2.23 MeV, and the distance between the nucleons is specified as 1 femtometer (fm). The gravitational potential energy is calculated using the formula -Gmm'/r, while it is noted that electric potential energy is absent; instead, magnetic energy exists between the nucleons' magnetic moments. However, these magnetic energies are negligible compared to the binding energy attributed to the nuclear force.

PREREQUISITES
  • Understanding of nuclear physics concepts, specifically nucleon interactions.
  • Familiarity with the formula for gravitational potential energy: -Gmm'/r.
  • Knowledge of binding energy in nuclear systems, particularly deuterium.
  • Basic grasp of magnetic moments and their relevance in nuclear interactions.
NEXT STEPS
  • Study the principles of nuclear force and its role in binding energy calculations.
  • Learn about the significance of magnetic moments in nuclear physics.
  • Explore advanced topics in potential energy calculations for multi-nucleon systems.
  • Investigate the differences between electric and magnetic potential energies in particle physics.
USEFUL FOR

Students and professionals in nuclear physics, physicists focusing on particle interactions, and anyone interested in the fundamental forces governing nucleon behavior.

VHP_KLJ
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Is it possible to caculate the electric potential energy and the gravitational potential energy between two nucleon of deuterium (1 proton, 1 neutron), if we know the binding energy of deuterium is 2.23 (MeV), and the distance between them is 1 (fm)?
Please help me! I'm really confused about this exercise :(
Thanks in advance
(I post this thread in wrong box, please move it, sorry)
 
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The gravitational energy is -Gmm'/r.
There is no electric PE, but there is magnetic energy between the two magnetic moments.
These energies are negligible compared to the 2,23 whic is due to the nuclear force.
 

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