Calculating Power Generated by DC Generator for 6V Battery

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SUMMARY

This discussion focuses on calculating the power generated by a DC generator to charge a 6V battery. The voltage output is determined using the formula E = N B v sin(theta), where E is the voltage, N is the number of turns, B is the flux density, and theta is the angle between the coil's vector and the magnetic field. To calculate actual power, the user needs to apply the formula P = V^2/R, where R is the resistance of the load. The goal is to use the generated power to illuminate a light bulb for a specified duration.

PREREQUISITES
  • Understanding of basic electromagnetism principles
  • Familiarity with DC generator operation
  • Knowledge of electrical power formulas
  • Basic circuit analysis skills
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This discussion is beneficial for hobbyists, electrical engineers, and anyone interested in renewable energy projects involving DC generators and battery charging systems.

cloud_skyblue
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Hi, I'm trying to work on this interesting little project that involves charging a 6V battery using a simple DC generator powered by a wheel spun manually. The equations for the DC generator output would be :


E = N B v sin(theta) x 10-8

if I'm correct. E being the voltage, N=number of turns, B=flux density, and theta is the angle between the coil's vector and the magnetic field.

My problem is, this only gives me the voltage. How would I get the actual power generated by the generator? All I know about the battery is that it is 6V and 5AH.

My goal is to have the battery power up a light bulb for a given duration. Any ideas?
 
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P = V^2/R

If the generator gives the impedance you can plug the numbers.
 

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