Calculating Power Output of Wind Turbine

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Homework Help Overview

The discussion revolves around calculating the power output of a wind turbine, specifically one with a swept diameter of 20 meters and an efficiency of 40%, subjected to an average wind speed of 10 m/s. Participants are exploring the relevant equations and parameters needed for this calculation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster seeks guidance on the appropriate equation for calculating power output, expressing confusion regarding additional factors like cut-in speeds. Some participants provide a formula for power calculation and attempt to apply it, while questioning the validity of their results and the assumptions made, particularly regarding air density.

Discussion Status

Participants are actively engaging with the problem, sharing calculations and questioning the accuracy of their results. There is a recognition of the need to clarify the swept area calculation, indicating a productive direction in the discussion.

Contextual Notes

There is mention of air density, which was not specified in the original problem statement, leading to some uncertainty in the calculations. Additionally, the original poster's reference to cut-in speeds suggests a potential area of confusion regarding wind turbine operation parameters.

JosephF
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Homework Statement



1. A wind turbine with a swept diameter of 20m and an efficiency of extracting energy from the wind of 40% is subjected to an average wind speed of 10m/s.
(a) How much power might the turbine produce?


Please can some one point me to the right equation as everyone I can find includes cut-in speeds etc...
 
Physics news on Phys.org
This link might be useful:
http://www.otherpower.com/windbasics1.html
 
Last edited by a moderator:
Thanks for the link.

P=0.5 * air density * swept area * wind velocity3

Taking air density as 1.23kg per cubic meter.

P=0.5 * 1.23 * 20 * 103

P=12,300Watts

40% efficent so output power is 4,920Watts.

Is this correct as the value seems quite high? Also there was no mention of air density in the question... Thanks,
 
JosephF said:
Thanks for the link.

P=0.5 * air density * swept area * wind velocity3

Taking air density as 1.23kg per cubic meter.

P=0.5 * 1.23 * 20 * 103

P=12,300Watts

40% efficent so output power is 4,920Watts.

Is this correct as the value seems quite high? Also there was no mention of air density in the question... Thanks,

Wikipedia said:
At sea level and 20 °C, air has a density of approximately 1.2 kg/m3.

They are after all 30 foot blades. That's a big area and a hefty chunk of air at 10m/s. I haven't calculated it out, but you would expect power in the kilowatts I would think.
 
You have calculated your "swept area" incorrectly.

You have used the diameter, not the area.

Remember area of circle = pi*r^2
 

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