Calculating Power Output of Wind Turbine

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SUMMARY

The discussion centers on calculating the power output of a wind turbine with a swept diameter of 20 meters and an efficiency of 40% under an average wind speed of 10 m/s. The power output is derived using the formula P=0.5 * air density * swept area * wind velocity^3, resulting in an initial calculation of 12,300 Watts. After accounting for efficiency, the output power is determined to be 4,920 Watts. Participants emphasize the importance of correctly calculating the swept area using the formula for the area of a circle, pi*r^2, rather than simply using the diameter.

PREREQUISITES
  • Understanding of wind turbine mechanics
  • Familiarity with the power output formula for wind turbines
  • Knowledge of calculating the area of a circle
  • Basic principles of air density and its impact on power calculations
NEXT STEPS
  • Research the impact of air density variations on wind turbine output
  • Learn about the effects of wind speed fluctuations on power generation
  • Explore advanced wind turbine efficiency optimization techniques
  • Study the relationship between blade design and swept area calculations
USEFUL FOR

Engineers, renewable energy enthusiasts, and students studying wind energy technology will benefit from this discussion, particularly those focused on wind turbine design and performance analysis.

JosephF
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Homework Statement



1. A wind turbine with a swept diameter of 20m and an efficiency of extracting energy from the wind of 40% is subjected to an average wind speed of 10m/s.
(a) How much power might the turbine produce?


Please can some one point me to the right equation as everyone I can find includes cut-in speeds etc...
 
Physics news on Phys.org
This link might be useful:
http://www.otherpower.com/windbasics1.html
 
Last edited by a moderator:
Thanks for the link.

P=0.5 * air density * swept area * wind velocity3

Taking air density as 1.23kg per cubic meter.

P=0.5 * 1.23 * 20 * 103

P=12,300Watts

40% efficent so output power is 4,920Watts.

Is this correct as the value seems quite high? Also there was no mention of air density in the question... Thanks,
 
JosephF said:
Thanks for the link.

P=0.5 * air density * swept area * wind velocity3

Taking air density as 1.23kg per cubic meter.

P=0.5 * 1.23 * 20 * 103

P=12,300Watts

40% efficent so output power is 4,920Watts.

Is this correct as the value seems quite high? Also there was no mention of air density in the question... Thanks,

Wikipedia said:
At sea level and 20 °C, air has a density of approximately 1.2 kg/m3.

They are after all 30 foot blades. That's a big area and a hefty chunk of air at 10m/s. I haven't calculated it out, but you would expect power in the kilowatts I would think.
 
You have calculated your "swept area" incorrectly.

You have used the diameter, not the area.

Remember area of circle = pi*r^2
 

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