Calculating Pressure - to Integrate or Not?

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erok81
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Homework Statement



This was a multi-part problem using the Clausius-Clapeyron relation to calculate how much pressure needed to be put on an ice cube in order to have it melt at -1*C.

Homework Equations



Clausius-Clapeyron relation given by:

[itex]\frac{dP}{dT}=\frac{L}{T\Delta V}[/itex]

The Attempt at a Solution



I am confused on how exactly to solve this. I've seen it two ways. One integrates and one doesn't, leading to two different answers.

The first is use just using ΔP/ΔT as just changes. So...

[itex]\frac{\Delta P}{\Delta T}=\frac{L}{T \Delta V}[/itex]

That's really it. Then one plugs in 272k for temp, then the value for ΔV that was calculated earlier, and L. Then just solve. I don't think this is the correct way.

The second method is integration.

[itex]\frac{dP}{dT}=\frac{L}{T\Delta V}[/itex]

[itex]\int ^{P_{f}}_{P{_i}} dP= \frac{L}{\Delta V} \int ^{T_{f}}_{T{_i}}\frac{dT}{T}[/itex]

Which, after adding Pi to both sides, the result is:

[itex]P_{f}=\frac{L}{\Delta V} ln(\frac{T_f}{T_i})+P_i[/itex]

And then plug in the same values, using the initial P and T as STP.

So my question is twofold, is the integration method correct? And this problem isn't the best example, but when is it needed to integrate vs. only use the Δ values?
 
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erok81 said:
The second method is integration.

[itex]\frac{dP}{dT}=\frac{L}{T\Delta V}[/itex]

[itex]\int ^{P_{f}}_{P{_i}} dP= \frac{L}{\Delta V} \int ^{T_{f}}_{T{_i}}\frac{dT}{T}[/itex]
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So my question is twofold, is the integration method correct?
Since the Clausius-Clapeyron relation involves dP/dT and not ΔP/ΔT, then integration is the correct method, strictly speaking.

And this problem isn't the best example, but when is it needed to integrate vs. only use the Δ values?
If you examine the integral you did, the question to ask is, "does the integrand change by very much in between the two limits of integration?"

The integrand is 1/T in the integral [itex]\int ^{T_{f}}_{T{_i}}\frac{dT}{T}[/itex]. What is the percentage change in 1/T, in going from 0°C to -1°C? Is that a large or a small change?