Calculating Projectile Motion: Solving for Distance and Height

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Homework Help Overview

The problem involves calculating the projectile motion of a ball tossed from a building, requiring the determination of horizontal distance, height, and time to a specific vertical point. The subject area is kinematics, focusing on motion under gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss resolving the initial velocity into horizontal and vertical components and question how to apply the equations of motion given the initial conditions.

Discussion Status

Some participants have offered guidance on breaking down the velocity into components and considering the vertical motion separately. There is an ongoing exploration of how to correctly apply the equations of motion, with no explicit consensus reached yet.

Contextual Notes

Participants express confusion regarding the initial velocity and its components, indicating a need for clarification on the setup and application of projectile motion equations.

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Homework Statement


A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8.20 m/s at an angle of 15.0° below the horizontal. It strikes the ground 3.00 s later.
(a) How far horizontally from the base of the building does the ball strike the ground?
4.90wrong check mark m
(b) Find the height from which the ball was thrown.
wrong check mark m
(c) How long does it take the ball to reach a point 10.0 m below the level of launching?



Homework Equations


i think the equations are r= v^2(sin2theta)/g
h= v^2(sintheta)2/2g


The Attempt at a Solution


i tried pluggin in the values to get how far it traveled and the height..but I am getting it wrong

any help would be appreciated
 
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Work out the velocity component downward.
Then it's just the normal moving object equations except the initial velocity isn't zero.
 
im not sure wat you mean by that

make the velocity -8.2?
im so confused
 
You need to resolve the velocity vector into horizontal and vertical components. Then, what mgb is saying, is you consider the vertical component.
 
o ok into two different components

so they give me 8.2 m/s
thats my resultant vector rite?

so i just do 8.2(cos15) ??
 
Draw a diagram (triangle) - it should be obvious how much of the diagonal speed goes horizontally and how much vertically.
 
alrite cool
thanks a lot guys
 

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