Calculating Quantum Number n for a Mass Moving in an Infinite Square Well

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Homework Help Overview

The discussion revolves around calculating the quantum number n for a mass in a one-dimensional infinite square well, given its mass and speed. Participants are exploring the relationship between kinetic energy and quantum mechanics in this context.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set up the problem using the kinetic energy formula and questions whether their setup is correct. Some participants suggest using the square of the speed in their calculations. Others seek clarification on the interpretation of energy in the context of the infinite square well.

Discussion Status

The discussion is ongoing, with participants providing guidance on the setup and interpretation of equations. There is an exploration of different interpretations regarding the nature of energy in the infinite square well scenario.

Contextual Notes

Participants are working within the constraints of a homework problem, which may limit the information available for the discussion. The definitions of potential and kinetic energy in the context of the infinite square well are also under examination.

UrbanXrisis
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a mass of 10^-6 grams is moving at a speed of 0.1 cm/s in a box 1 cm in length. Treating this as a 1-D infinite square well, i am to calculate the quantum number n:

i was wondering if I am setting this up correct:
[tex]\frac{1}{2} * 10^{-6 }g * 0.1 cm/s = \frac{n^2 \pi^2 \hbar ^2}{2*10^{-6 }g * 1cm^2}[/tex]
 
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Just use v^2 on the LHS.
 
so [tex]E= \frac{n^2 \pi^2 \hbar ^2}{2mL}[/tex]
is really kinetic energy?
 
UrbanXrisis said:
so [tex]E= \frac{n^2 \pi^2 \hbar ^2}{2mL}[/tex]
is really kinetic energy?

Not exactly. E = T + V. But since this is an infinite square well and the region you have has V defined as zero...

-Dan
 

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