Calculating radius in circular motion without frequency or force?

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InertialRef
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Homework Statement



Scientists want to place a 4400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2645.0 m/s in a perfectly circular orbit. Here is some information that may help solve this problem:

mmars = 6.4191 x 1023 kg
rmars = 3.397 x 106 m
G = 6.67428 x 10-11 N-m2/kg2

What radius should the satellite move at in its orbit? (Measured from the center of Mars.)

Homework Equations



v = 2∏r/T

The Attempt at a Solution



This question makes no sense. Is there any way to calculate the period of the motion using a different equation? Otherwise, there are two unknowns, irrespective of which equation is used. Even if I attempt to use two different equations that are solved for T and equate them, there is always an unknown such as frequency or acceleration present along with radius.
 
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InertialRef said:

Homework Statement



Scientists want to place a 4400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2645.0 m/s in a perfectly circular orbit. Here is some information that may help solve this problem:

mmars = 6.4191 x 1023 kg
rmars = 3.397 x 106 m
G = 6.67428 x 10-11 N-m2/kg2

What radius should the satellite move at in its orbit? (Measured from the center of Mars.)

Homework Equations



v = 2∏r/T

The Attempt at a Solution



This question makes no sense. Is there any way to calculate the period of the motion using a different equation? Otherwise, there are two unknowns, irrespective of which equation is used. Even if I attempt to use two different equations that are solved for T and equate them, there is always an unknown such as frequency or acceleration present along with radius.

If the object is moving in a *circle*, then just as a kinematic requirement, what kind of force must be acting on it? What physical force in this problem is acting as that force (that keeps it moving in a circle)?
 
Ahh, universal law of gravitation. Okay, I think I might have a handle on this. Thank you.