- #1

- 19

- 0

mmars = 6.4191 x 10^23 kg

rmars = 3.397 x 10^6 m

G = 6.67428 x 10^-11 N-m2/kg2

I know F = G * m * M /r^2

But what should I plug for r , m , M , G

- #1

- 19

- 0

mmars = 6.4191 x 10^23 kg

rmars = 3.397 x 10^6 m

G = 6.67428 x 10^-11 N-m2/kg2

I know F = G * m * M /r^2

But what should I plug for r , m , M , G

- #2

- 34,639

- 6,004

Start by making some suggestions that look reasonable to you.what should I plug for r , m , M , G

- #3

- 34,639

- 6,004

What do you understand the various symbols to stand for in the equation?what should I plug for r , m , M , G

- #4

- 19

- 0

m= 6.4191 x 10^23

G = is either 9.8 or 6.67428 x 10^-11

M= 2900

r=(1.6* 3.397 x 10^6) or 3.397 x 10^6

- #5

- 34,639

- 6,004

There's not much point in knowing an equation if you don't know what the variables in it represent. In this one, G is the gravitational constant, not 'g', the acceleration due to gravity at earth's surface. The dimensions of the two are quite different. If you track the units through your working (and it is a very good idea to do that) you'll see that using 9.81 m/s

m= 6.4191 x 10^23

G = is either 9.8 or 6.67428 x 10^-11

M= 2900

r=(1.6* 3.397 x 10^6) or 3.397 x 10^6

r is the distance between the masses. In principle, this should refer only to point masses. Gravitational attraction between two bodies of arbitrary shape can get pretty nasty. But luckily, the equation also works when the bodies are spherical and uniformly dense*. In this case, you take r to be the distance between the mass centres.

[*In fact, they don't need to be uniformly dense. It is enough that, in each, the density is only a function of distance from the centre.]

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