Understanding formula F=GmM/r^2 confusion help

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SUMMARY

The discussion focuses on calculating the gravitational force of attraction between Mars and a 2900.0 kg satellite using the formula F=GmM/r^2. The relevant constants include Mars' mass (6.4191 x 10^23 kg), its radius (3.397 x 10^6 m), and the gravitational constant (G = 6.67428 x 10^-11 N-m²/kg²). The satellite orbits at a distance of 1.6 times the radius of Mars above the planet's surface. The calculation involves substituting these values into the formula to determine the gravitational force.

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Homework Statement



Scientists want to place a 2900.0 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 1.6 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:



mmars = 6.4191 x 10^23 kg
rmars = 3.397 x 10^6 m
G = 6.67428 x 10^-11 N-m2/kg2

1) What is the force of attraction between Mars and the satellite?




Homework Equations



F=GmM/r^2

The Attempt at a Solution




((6.67428e-11)*(6.491e+23)*(2900))/(1.6*3.397e+6)^2
 
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Where is the satellite's height measured from?
 

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