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Understanding formula F=GmM/r^2 confusion help !

  1. Jan 29, 2013 #1
    1. The problem statement, all variables and given/known data

    Scientists want to place a 2900.0 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 1.6 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:



    mmars = 6.4191 x 10^23 kg
    rmars = 3.397 x 10^6 m
    G = 6.67428 x 10^-11 N-m2/kg2

    1) What is the force of attraction between Mars and the satellite?




    2. Relevant equations

    F=GmM/r^2

    3. The attempt at a solution


    ((6.67428e-11)*(6.491e+23)*(2900))/(1.6*3.397e+6)^2
     
  2. jcsd
  3. Jan 29, 2013 #2

    tms

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    Where is the satellite's height measured from?
     
  4. Jan 29, 2013 #3

    Dick

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