Calculating Re and Ib for Transistor Saturation Region

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To ensure the transistor operates in the saturation region, the values of Re and Ib must be accurately calculated. Given the circuit parameters, Vre is determined to be 4.3 volts, leading to an initial calculation of Re as 0.86 KΩ based on Ic. However, this calculation does not account for additional currents from Vcc or V1 through Re, necessitating the application of Kirchhoff's laws for a more precise analysis. The equations derived from Kirchhoff's laws will help find Vce and Ic, which are crucial for confirming the transistor's saturation state. Accurate calculations of Re and Ib are essential for proper transistor function in the saturation region.
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i should find Re so that transistor works in saturation region

also i should find Ib in saturation region

Rc=2kΩ , R1=2kΩ , EB=5V, Vcc=10V, V1=3V, β=100

im really confused with R1 and V1 i don't know what is their function

i know that in saturation region Vce = 0

also from the diagram i can see that

Eb - 0.7 = Vre so Vre = 4.3 Volts

Ie = Vre/Re

if we assume that Ie = Ic

then

Ic = Vre/Re

Ic is Vcc/Rc = 10/2000 = 5mA

so Re should be Vre/5mA = 4.3/5*10^-3 = 0.86 KΩ

but does this Re stand for saturation region?
 
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Your calculation for Ie doesn't take into account current flowing due to Vcc or V1 in the resistor Re. Use Kirchoff's laws.
 
we have

Eb - 0.7 = Ic1*Re we find Ic1 from Eb

Vcc - Ic(Rc+Re) - Vce = 0
V1 - Ic(R1+Re) - Vce = 0

we find Vce from these two statements and Ic which I will have to add Ic1?

and how can this help me solve the problem?
 

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