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BJT Biasing - Simple easy 1 minute answer!

  1. Feb 3, 2012 #1
    1. The problem statement, all variables and given/known data
    Find IB, IC, IE, VCE, VBC, and VEB for the NPN transistor in the circuit below for β = 50, 150, 500. Let VCC = 10 V, R1 = 100 KΩ, R2 = 400 KΩ, RC=2 KΩ, and RE = 0 Ω. Assume VBE = 0.7V.


    2. Relevant equations

    V = iR
    IE = Ib + Ic


    3. The attempt at a solution

    My question is that if RE = 0 ohms, then is Ie automatically 0 amps?

    But the how does Ie = Ib + Ic apply? Because I got 92.25uA for Ib and 4.56mA for Ic?

    Help! :]
     
  2. jcsd
  3. Feb 3, 2012 #2
    Forgot to put the figure :]
     

    Attached Files:

  4. Feb 3, 2012 #3

    NascentOxygen

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    Staff: Mentor

    No. A piece of connecting wire from emitter to ground = 0 Ω :smile:
     
  5. Feb 3, 2012 #4

    Awwww!

    :[ So Ie = Ib + Ic is correct?

    I would use this to calculate Ie?
     
  6. Feb 3, 2012 #5

    NascentOxygen

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    Staff: Mentor

    Yes.

    It is involved in the calculations.
     
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