Calculating Required Force for Pushing a Block on an Inclined Ramp

  • Thread starter Thread starter jolee'11
  • Start date Start date
  • Tags Tags
    Force Ramp
Click For Summary
SUMMARY

The required force to push an 870 kg block up an 80 m ramp at a constant speed is calculated using the coefficient of sliding friction of 0.32 and an incline angle of 16 degrees. The correct approach involves applying Newton's second law, ensuring all units are consistent, specifically using kg*m/s². The equation must account for both the frictional force and the gravitational component acting along the ramp, which is derived from the sine of the incline angle.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of trigonometric functions, specifically sine
  • Familiarity with the concept of friction and its coefficient
  • Ability to manipulate units in physics equations
NEXT STEPS
  • Study the derivation of forces on inclined planes in physics
  • Learn how to calculate frictional forces in different scenarios
  • Explore the application of trigonometric functions in physics problems
  • Review unit conversion techniques in physics equations
USEFUL FOR

Students in physics courses, educators teaching mechanics, and anyone involved in solving problems related to forces on inclined surfaces.

jolee'11
Messages
1
Reaction score
0
HELP! FORCE with RAMP!

Homework Statement



What force is required to push a 870kg block up an 80m ramp at a constant speed. The block has a coefficient of sliding friction of .32 with the ramp, and angle of 16 degrees from the ground.

Homework Equations





The Attempt at a Solution


F=(.32)+((870)(9.81)(sin(16))?
 
Physics news on Phys.org


Well, first you should realize that your units don't match up. You can only add similar units, and they should be the same as the units on the other side of the equal sign. Try rearranging your variables to give units of kg*m/s^2. Currently, you are attempting to add a unit-less coefficient to something with units of kg*m/s^2.
 


If you get stuck again, let me know, and don't forget to use Newton's second law for a system in equilibrium (sigma)F = 0
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
Replies
10
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 56 ·
2
Replies
56
Views
5K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
1K