Calculating Required Torque for Rotating an Object at 1RPM in 1 Second

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To calculate the required torque to rotate an object from 0 to 1 RPM in 1 second, the torque formula used is Torque = Force x radius, with the radius being 0.005 meters. The object weighs 20 kg and is on a low friction bearing, leading to the calculation of force as mass times acceleration. The acceleration is derived from the final velocity of 0.0314 m/s divided by time, resulting in a torque equation of T = 0.186/t Nm. The discussion highlights the user's need for further guidance in engineering concepts, despite having followed online examples correctly.
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Hi I am trying to work out the torque required to rotate an object from 0 to 1RPM in 1 second (1 second accelerate to 1RMP) , its working in time laps so very small movement is required.

The diameter of the gear is 30mm and the diameter of the shaft is 10mm, the object on top weights 20kg it's sitting on a low friction bearing.

So far I have

Torque = F x r

r = radius of the cylinder = 0.005

Force = mass x acceleration
where mass = 20kg

accel = velocity/time

velocity = r x ω (rotational speed)

where ω at 1RPM = 6.28 rad/sec

So v = 0.005 x 6.28 = 0.0314 m/s

Therefore accel = 0.0314/t

Therefore T = 12 x 0.031/t x 0.005
= 0.186/t Nm

I know there is a lot more to this but I am very new to this and out of my comfort zone in terms of engineering knowledge (I'm a product designer) , I've mainly been following pre worked examples I've found online. Would really appreciate some help and guidance.
 
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