Calculating Resistance at Multiple Points in a Resistor Network

Click For Summary
SUMMARY

This discussion focuses on calculating resistance at multiple points (bc, cd, and da) in a resistor network using Kirchhoff's law and Ohm's law. Participants emphasize the importance of redrawing circuits to identify nodes and simplify the analysis of resistors, particularly the 10 ohm and 15 ohm resistors connected in parallel. The recommended approach includes simplifying the circuit by replacing parallel resistances with their equivalent resistance before calculating the required values. Clear understanding of circuit configuration is essential for effective problem-solving in this context.

PREREQUISITES
  • Understanding of Kirchhoff's law
  • Familiarity with Ohm's law
  • Knowledge of series and parallel resistor configurations
  • Ability to redraw electrical circuits for analysis
NEXT STEPS
  • Study the principles of circuit simplification in resistor networks
  • Learn how to calculate equivalent resistance for parallel and series resistors
  • Explore examples of circuit analysis using nodes
  • Investigate online resources or textbooks on network analysis techniques
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing resistor networks and improving their circuit analysis skills.

Eucliwood
Messages
17
Reaction score
0
Homework Statement
Finding the resistance when probed at point bc, cd and da
Relevant Equations
Series and Parallel resistance equation derived from kirchhoff's law with application of ohm's law
Problem Statement: Finding the resistance when probed at point bc, cd and da
Relevant Equations: Series and Parallel resistance equation derived from kirchhoff's law with application of ohm's law

I genuinely don't know what to do on this one. The example our professor made isn't exactly clear and I haven't find any online solution. I just wanted to know how would one calculate the value from those points.
 

Attachments

  • 59498504_592447804600815_4296939557867225088_n.jpg
    59498504_592447804600815_4296939557867225088_n.jpg
    13.6 KB · Views: 251
Physics news on Phys.org
First of all, it's rude to post your figures sideways.

This is mainly a problem in learning to redraw circuits so as to recognize where you can combine elements. If you haven't yet learned how to do that, this problem is going to be tough.

What do you notice about the 10 ohm and 15 ohm resistors?
 
A node is a point wherein 3 or more wires constitutes it and the connection is in parallel. I don't know what point to look. But, if i were look at point d the 10 and 15 ohm resistors are connected in parallel. Sorry for the image.
 
I'd be glad if you were to include an example in resistors configuration with nodes on it. If it weren't much of a trouble. I cannot find a website that teaches network analysis with nodes embedded.
 
First of all, it's rude to post your figures sideways.

This is mainly a problem in learning to redraw circuits so as to recognize where you can combine elements. If you haven't yet learned how to do that, this problem is going to be tough.
Eucliwood said:
A node is a point wherein 3 or more wires constitutes it and the connection is in parallel. I don't know what point to look. But, if i were look at point d the 10 and 15 ohm resistors are connected in parallel. Sorry for the image.
Since the 10 and 15 ohm resistors are in parallel, don't you think that would be a good first step in simplifying the circuit?
 
phinds said:
First of all, it's rude to post your figures sideways.

This is mainly a problem in learning to redraw circuits so as to recognize where you can combine elements. If you haven't yet learned how to do that, this problem is going to be tough.

Since the 10 and 15 ohm resistors are in parallel, don't you think that would be a good first step in simplifying the circuit?
 

Attachments

  • 59622039_642671756196226_7512308365217759232_n.jpg
    59622039_642671756196226_7512308365217759232_n.jpg
    10 KB · Views: 251

So is this right for Rab?
 

Attachments

  • 59583070_348657889342049_7522145270549708800_n.jpg
    59583070_348657889342049_7522145270549708800_n.jpg
    45.6 KB · Views: 255
Eucliwood said:
So is this right for Rab?
No. There's a direct path from a to b and and a path that goes through c and d, that's parallel to the direct path.

I would redraw the circuit first with only the points a,b,c,d in it. and replacing all parallel resistances between those points with the equivalent resistance. You can than use that to compute the 3 resistances needed.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
4
Views
2K
Replies
15
Views
4K
Replies
4
Views
5K
  • · Replies 28 ·
Replies
28
Views
9K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
1K
Replies
4
Views
3K