Calculating Resistance in a Parallel Circuit without Voltage Information

AI Thread Summary
To calculate the resistance of R3 in a parallel circuit without voltage information, the total current from the power supply is 250 mA, with 54 mA flowing through R3. The voltage across each resistor is equal to the battery voltage, which can be determined using Ohm's law (V=IR). By finding the equivalent resistance of the other resistors and subtracting the current through R3 from the total current, the voltage can be calculated. Ultimately, the resistance of R3 is found to be approximately 334 ohms.
Aleena753
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Homework Statement


Three resistors are connected as shown in the diagram. If the current from the power supply is 250 mA and the current through R3 is 54 mA, what is the resistance of R3?
FullSizeRender (2).jpg


Homework Equations


1/Req= 1/R1 + 1/R2 +1/R3

V=IR

The Attempt at a Solution



First I used the parallel circuit formula of 1/Req= 1/R1+ 1/R2 + 1/R3
but there are two variables (Req and R3) so I'm not sure how to use that. Also, there's no voltage provided so I'm a bit confused as how to go from here. Any help would be appreciated :)
 
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You can see that the resistors are in parallel, meaning voltage across each resistor is equal to the battery voltage.
Aleena753 said:
current from the power supply is 250 mA
Aleena753 said:
and the current through R3 is 54 mA,
Could you calculate voltage of the battery from this information?
Hint: Ohm's law and resistances in parallel.
 
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I had an idea for finding the solution. I was thinking that I could find the total V and then divide it by the total current to find Req and then use that Req in the parallel circuit formula (1/Req= 1/R1 + 1/R2 + 1/R3) to find R3. As for the total voltage of the battery, I know to use V=IR but I'm not sure which numbers to use, since the current of the two known resistors is unknown.
 
Aleena753 said:
since the current of the two known resistors is unknown.
Well, you can combine the two known resistances by finding their equivalent resistance. You can then calculate current through the equivalent resistance and apply Ohm's law.
 
So the current for the equivalent resistance of R1 and R2 would be the total current of the circuit with the current of the third resistor subtracted right?
 
Aleena753 said:
So the current for the equivalent resistance of R1 and R2 would be the total current of the circuit with the current of the third resistor subtracted right?
Right.
 
I had an idea for finding the solution. I was thinking that I could find the total V and then divide it by the total current to find Req and then use that Req in the parallel circuit formula (1/Req= 1/R1 + 1/R2 + 1/R3) to find R3. As for the total voltage of the battery, I know to use V=IR but I'm not sure which numbers to use, since the current of the two known resistors is unknown.[/QUOTE]
cnh1995 said:
You can see that the resistors are in parallel, meaning voltage across each resistor is equal to the battery voltage.Could you calculate voltage of the battery from this information?
Hint: Ohm's law and resistances in parallel.
cnh1995 said:
Right.
So I found the voltage and then divided it by the third current (54mA) to find the resistance of the third resistor. I currently have what I believe is the right answer of 333 ohms.
 
Aleena753 said:
I currently have what I believe is the right answer of 333 ohms.
I'm getting 334.something ohms. But your method is correct.
 
cnh1995 said:
I'm getting 334.something ohms. But your method is correct.
Alright thank you for your help : )
 
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