What is voltage when running current through copper plats?

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SUMMARY

The discussion centers on calculating the voltage generated when running current through copper plates, specifically in the context of a solenoid design using bitter disks made of a copper-silver alloy. The calculations provided utilize Ohm's Law (V = IR) and the resistance formula (R = ρL/A) to determine that the voltage is approximately 0.00001524 volts when a current of 0.086 amps is applied. The resistance of the copper disks is calculated to be 0.0001772 ohms, indicating minimal voltage generation under the specified conditions. The discussion also raises questions about the impact of overlapping copper plates and insulation on resistance and voltage.

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  • Understanding of Ohm's Law and its application in electrical circuits
  • Knowledge of electrical resistance and resistivity, particularly for copper
  • Familiarity with solenoid design principles and magnetic fields
  • Basic geometry for calculating cross-sectional areas and circumferences
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Matt01
Hey everyone, I'm hoping that you guys will be able to help me with some calculations. I was on YouTube and came across this:


I then began to wonder if I could make a solenoid using bitter disk as in the video, granted no where near as powerful. I would say 1 tesla using an iron core. After some digging, I found the bitter disk are .27 mm thick or thicker and as the video says made of a copper silver alloy. To simplify let's use pure copper. Since current generates heat, and as heat increases, so do the resistance of the copper, let's say the copper disks are being called by water or some other cooling mechanism to keep them at room temps.

Known:

B=unl
length is 12inches/.3048m
r = 1 inch
bitter disk would need to be big enough for the iron to go through and extend 2 inches out from the inner edge.
turns = 564.4
There would be 564.4 insulators
turn density is n=N/L = 1850 turns/m
I = 0.086 amps
B = 1 tesal
u = relative permeability = Iron (99.8% pure) 6.3 10−3 5000
source: https://www.engineeringtoolbox.com/permeability-d_1923.html

Ohm's Law : V = IR
V = volts
I = current in amps
R = resistance
R = ρL/A = Resistance of the wire(bitter disk)
P = Resistivity of copper ρ = 1.7 x 10-8 Ωm
L = is the length
A = The area is the cross-sectional area of the wire

Unknown:

My best guess for the cross-sectional area of the bitter disk would be: a = L*w
a = 50.8 mm * .27 mm = 8.636 mm ^2 = 0.008636 m^2
My best guess for the length the current would travel would be to take the circumference of a circle or in this case the bitter disk * number of turns and convert to meters.
c = 2 π r = 2 * π * 25.4mm = 159.593 mm = 0.159593m * 564 = 90.01m
(1.7 x 10-8 Ωm * 90.01m)/ (0.008636 m^2)
R = 0.0001771850393700787Ω
V = IR
V = 0.086 amps * 0.0001771850393700787Ω = 0.0000152379133858267682 volts
V = 0.00001524 volts

Questions:

What would the voltage be?
Would the overlapping copper plates add more resistance and increase the voltage?
Would the insulation between the copper plates add resistance?
 
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