Calculating Resultant Force and Acceleration in a Simple Vector Problem

Click For Summary
SUMMARY

The discussion focuses on calculating the resultant force and acceleration of a child weighing 450 N on a fairground ride, subjected to a force P at a 35° angle to the vertical. The resultant force was calculated as 315 N, with the child's acceleration directed horizontally to the left. However, there is a discrepancy in the acceleration calculation; the participant calculated 7.00 m/s² using an approximation of g as 10 m/s², while the textbook used 9.8 m/s², resulting in a corrected acceleration of 6.86 m/s².

PREREQUISITES
  • Understanding of vector forces and their components
  • Knowledge of Newton's second law (F = ma)
  • Familiarity with trigonometric functions for angle calculations
  • Basic principles of gravitational force (g = 9.8 m/s²)
NEXT STEPS
  • Review vector resolution techniques in physics
  • Study the impact of gravitational acceleration on force calculations
  • Learn about the significance of significant figures in scientific calculations
  • Explore the differences between using approximate and exact values in physics problems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and vector analysis, as well as educators looking for examples of force and acceleration calculations.

furor celtica
Messages
69
Reaction score
0

Homework Statement



A child has weight 450 N. Whilst on a fairground ride the child is subject to a force P acting at 35° to the upward vertical, as shown in the diagram. Given that the resultant of P and the child’s weight acts horizontally,
a. Find the magnitude of the resultant
b. State the direction of the child’s acceleration
c. Find the magnitude of the child’s acceleration


Homework Equations





The Attempt at a Solution


My answers were the following
a. 315 N (to 3 s.f.)
b. The child’s acceleration is directed horizontally to the left
c. 7.00 m(s^2) (to 3 s.f.)

According to the textbook, my first two answers are correct, but the third is given as 6.86 m(s^2).
How is this possible? a = F/m = 315 / 45 = 7 m(s^2). Did I miss something?
 
Physics news on Phys.org
forgot the diagram
 

Attachments

  • Untitled.png
    Untitled.png
    1.2 KB · Views: 528
The book is using 9.8 m/s^2 for g, whereas you (apparently) used 10 m/s^2.
 

Similar threads

Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 30 ·
2
Replies
30
Views
2K
Replies
26
Views
4K
Replies
6
Views
4K
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
3
Views
4K
Replies
6
Views
3K