Calculating RMS Value of i=1/3sin3t

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SUMMARY

The RMS value of the function i=1/3sin(3t) over the interval from t=0 to t=1/10 can be calculated using the formula V_{rms} = √{(1/(t_1-t_0)) ∫_{t_0}^{t_1} [f(t)]^2 dt}. This method involves integrating the square of the function over the specified interval and then taking the square root of the average value. The integral must be evaluated from t=0 to t=1/10 to obtain the RMS value definitively.

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  • Understanding of calculus, specifically integration techniques.
  • Familiarity with the concept of root mean square (RMS).
  • Knowledge of continuous functions and their properties.
  • Basic skills in evaluating definite integrals.
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robbieharibo
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1. find the rms value of i=1/3sin3t between t=0 and t=1/10



2. not sure of the method or the formula i may need



3. Any help appreciated
 
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For continuous functions the RMS over a time interval is

[tex]\sqrt{ \frac{1}{T_2 - T_1} \int_{T_1}^{T_2} [f(t)]^2 dt[/tex]
 
robbieharibo said:
1. find the rms value of i=1/3sin3t between t=0 and t=1/10



2. not sure of the method or the formula i may need



3. Any help appreciated


rms is root mean squared

[tex] <br /> V_{rms} = \sqrt{\frac{1} {(t_1-t_0)}\int_{t_0}^{t_1} v(t)^2 dt}[/tex]
 

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