Calculating Sam's Jet Ski Coasting Distance and Top Speed

Click For Summary
SUMMARY

Sam's Jet Ski, with a thrust of 200N and a mass of 75 kg, achieves a top speed of 16.9 m/s after 10 seconds of acceleration. The net force acting on the skis, calculated as 126.5N, leads to an acceleration of 1.69 m/s². To determine the distance traveled while coasting to a stop, the deceleration due to kinetic friction (7.35N) must be calculated, which will then be used in the kinematic equation Vf² = Vi² + 2a (deltaX) to find the displacement.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of kinematic equations
  • Familiarity with concepts of friction and net force
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate deceleration due to friction for coasting distance
  • Apply kinematic equations to find displacement during coasting
  • Explore the effects of varying coefficients of friction on motion
  • Investigate impulse and momentum concepts in collision scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking for practical examples of kinematic equations and forces in action.

kraaaaamos
Messages
20
Reaction score
0

Homework Statement


Sam, whose mass is 75 kg, takes off across level snow on his jet-powered skis. The skis have a thrust of 200N and a coefficient of kinetic friction on snow of 0.10. Unfortunately, the skis run out of fuel after only 10 s.

a. What is Sam’s top speed?
b. How far has Sam traveled when he finally coasts to a stop?

Homework Equations





The Attempt at a Solution



Fnet = F(thrust) - Fk
where Fk = (coeff)mg
= (0.1)(75)(9.8)
= 73.5N
plug into Fnet = F (thrust) - Fk
= 200 - 73.5
= 126.5N

To find acceleration:
Fnet = ma
126.5 = 75 a
a = 126.5/75
a = 1.69 m/s2

To find top speed:
Vf = Vi + a (deltaT)
Vf = 0 + 1.69(10)
= 16.9m/s

to find b... i have no idea.
i knwo that:
vi would be 16.9m/s
vf would be 0m/s
i don't know what the decelleration value is for when it is coasting
and i knwo that i use the equation: Vf^2 = Vi^2 + 2a (deltaX)
wehre delta (X) is change in position (displacment)

someone help!
 
Last edited:
Physics news on Phys.org
Now the frictional force is the retarding force. From that find the decelleration.
 
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 58 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the force on him from the snow was at the survivable limit of 1.2 105 N.

(a) What is the minimum depth of snow that would have stopped him safely?

?m

(b) What is the magnitude of the impulse on him from the snow?


? kg·m/s

PLEASE HELP ON THIS PROBLEM
ANY HELP ON THIS PROBLEM WILL BE GREATLY APPRECIATED
 
Show some work in the second problem
 

Similar threads

Replies
9
Views
4K
Replies
6
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
8K
Replies
1
Views
5K
  • · Replies 11 ·
Replies
11
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
20K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
3
Views
9K