What Is Sam's Top Speed and Travel Distance on Jet Powered Skis?

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SUMMARY

Sam's jet powered skis, with a thrust of 189N and a coefficient of kinetic friction of 0.1, achieve a top speed of 16.578 m/s after 12 seconds of operation. The calculation for acceleration utilized the formula F - uk(n) = m(Ax), resulting in an acceleration of 1.3815 m/s². For the distance traveled before coming to a stop, the correct approach involves equating the work done by friction to the kinetic energy of the skier, leading to a displacement of 198.936 meters, which was initially miscalculated.

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  • Understanding of Newton's second law (F=ma)
  • Knowledge of kinetic friction and its calculation (Fk = uk(n))
  • Familiarity with kinematic equations, specifically Vxf^2 = Vxi^2 + 2(Ax)(delta x)
  • Basic principles of work-energy theorem
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Homework Statement



Sam, whose mass is 80 kg, takes off across level snow in his jet powered skis. The skis have a thrust of 189N and a coefficient of kinetic friction on snow of 0.1. Unfortunately, the skis run out of fuel after only 12s. a.) What is Sam's top speed? b.) How far has Sam traveled when he finally coasts to a stop?

Homework Equations



Fk = uk(n)
F=ma

The Attempt at a Solution


I solved part A by using F-uk(n) = m(Ax). I solved for Ax, and got the answer to be 1.3815. I then used acceleration = velocity/time to find the velocity. I got the velocity to be 16.578, which is right. For part B I tried using Vxf^2 = Vxi^2 + 2(Ax)(delta x) to find the change in displacement. I got 198.936m, which was wrong.
 
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For the second part use the fact that
Frictional_force x distance = work_done_to_stop_skier = kinetic_energy_of_skier.
 

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