Coefficient of kinetic friction of skis

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SUMMARY

The coefficient of kinetic friction (uk) for Sam's jet-powered skis on snow is calculated to be 0.165. This conclusion is derived from applying the work-energy principle, considering Sam's mass of 75 kg, a slope height of 50 m, and a thrust force of 200 N. The final speed at the bottom of the slope is 40 m/s, which is essential for determining the net forces acting on the skis. The formula used is Fk = uk N, where N represents the normal force.

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  • Knowledge of forces acting on an inclined plane
  • Basic algebra for solving equations
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Homework Statement



Sam, whose mass is 75 kg , takes off down a 50 m high, 10 degree slope on his jet-powered skis. The skis have a thrust of 200N . Sam's speed at the bottom is 40 m/s . What is the coefficient of kinetic friction of his skis on snow?


Homework Equations



Fk = uk N
u = Fk / N


The Attempt at a Solution



there's an answer to this question in the back of my book and I've been trying to figure out why the author got this answer uk = 0.165 . The reason I am doing this is to apply the same technique to figure another problem like this on masteringphysics.com. Thank you for your help!
 
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Use work-energy principle.
 

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