Calculating Sam's Jet Ski Coasting Distance and Top Speed

Click For Summary

Homework Help Overview

The discussion revolves around two physics problems involving motion and forces. The first problem concerns Sam's jet-powered skis, focusing on calculating his top speed and the distance he coasts to a stop after running out of fuel. The second problem involves a paratrooper's fall and the forces acting on him upon landing in snow.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the net force and acceleration for Sam's skis but expresses uncertainty about finding the deceleration during coasting. Another participant suggests determining the deceleration from the frictional force. In the second problem, the poster requests assistance with calculations related to impulse and stopping distance.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problems. Some guidance has been offered regarding the calculation of deceleration, but no consensus has been reached on the complete solutions for either problem.

Contextual Notes

The original poster indicates a lack of clarity on how to proceed with the second part of the first problem, particularly regarding the deceleration while coasting. Additionally, there is a request for help on the second problem, highlighting the need for further assistance in understanding the concepts involved.

kraaaaamos
Messages
20
Reaction score
0

Homework Statement


Sam, whose mass is 75 kg, takes off across level snow on his jet-powered skis. The skis have a thrust of 200N and a coefficient of kinetic friction on snow of 0.10. Unfortunately, the skis run out of fuel after only 10 s.

a. What is Sam’s top speed?
b. How far has Sam traveled when he finally coasts to a stop?

Homework Equations





The Attempt at a Solution



Fnet = F(thrust) - Fk
where Fk = (coeff)mg
= (0.1)(75)(9.8)
= 73.5N
plug into Fnet = F (thrust) - Fk
= 200 - 73.5
= 126.5N

To find acceleration:
Fnet = ma
126.5 = 75 a
a = 126.5/75
a = 1.69 m/s2

To find top speed:
Vf = Vi + a (deltaT)
Vf = 0 + 1.69(10)
= 16.9m/s

to find b... i have no idea.
i knwo that:
vi would be 16.9m/s
vf would be 0m/s
i don't know what the decelleration value is for when it is coasting
and i knwo that i use the equation: Vf^2 = Vi^2 + 2a (deltaX)
wehre delta (X) is change in position (displacment)

someone help!
 
Last edited:
Physics news on Phys.org
Now the frictional force is the retarding force. From that find the decelleration.
 
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, suffering only minor injuries. Assume that his speed at impact was 58 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the force on him from the snow was at the survivable limit of 1.2 105 N.

(a) What is the minimum depth of snow that would have stopped him safely?

?m

(b) What is the magnitude of the impulse on him from the snow?


? kg·m/s

PLEASE HELP ON THIS PROBLEM
ANY HELP ON THIS PROBLEM WILL BE GREATLY APPRECIATED
 
Show some work in the second problem
 

Similar threads

Replies
9
Views
4K
Replies
6
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
8K
Replies
1
Views
5K
  • · Replies 11 ·
Replies
11
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
20K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
3
Views
9K