Calculating Specific Heat of a Tin Sample: A Quick Question and Solution

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Homework Help Overview

The discussion revolves around calculating the specific heat of a tin sample based on a heat transfer problem involving tin and water. The scenario includes a 250 gram piece of tin at 99 degrees Celsius being placed in 100 grams of water at 10 degrees Celsius, with a final temperature of 20 degrees Celsius.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are examining the temperature conversions to Kelvin and questioning the origin of specific temperature differences used in the calculations. There is also a focus on ensuring the correct application of the temperature conversion formula.

Discussion Status

The discussion is active, with participants questioning the temperature conversions and the assumptions made in the problem setup. Some guidance has been offered regarding the heat transfer relationship between the tin and water, but no consensus has been reached on the specific temperature values or their conversions.

Contextual Notes

There is a mention of the need to include appropriate units in the calculations, and participants are clarifying the temperature conversion process, which may indicate a lack of clarity in the problem's initial setup.

Aikenfan
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I saw this problem online...

A 250 gram piece of tin at 99 degrees C. is dropped into 100 grams of water at 10 degress C. If the final temperature is 20 degrees C., calculate the specific heat of the tin sample. Be sure to include the appropriate units !
Note c for water = 4.186 KJ/kg.K

Solution 41766

Assume K = 273.15 + C where K is Kelvin and C is Celsius.
Hints:
Let the specific heat of tin be x kJ/(kg*K).
0.250 * x * (372.15 - 293.15) = 0.100 * 4.186 * (293.15 - 283.15)
Solve for x.

and i just wondered...where did the (372.15 - 293.15) come from? thank you very much!
 
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what are the 3 temps after converting to Kelvin?

then heat lost by tin=heat rise of water
 
99--- - 174.15
10---- -263.15
20---- -253.15
 
you sure, k=273.15+C
 

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