Calculating Heat Transfer: Specific Heat Homework"

[appdulrahman]

Homework Statement

Homework Equations

Is my work right? This is the last attempt I got :/

The Attempt at a Solution

Specific heat of water = 4.187 J/g.K
Heat released by hot metal = mass x specific heat x temperature change
= 99 x c x (100 - 21.4) = 7781.4c
Heat absorbed by water = mass x specific heat x temperature change
= 403 x 4.187 x (21.4 - 20.0) = 2362.305 J
Heat absorbed by container = mass x specific heat x temperature change
= 212 x c x (21.4 - 20.0) = 296.8c
Total heat released = total heat absorbed
7781.4c = 2362.305 + 296.8c
Specific heat of the metal = c = 0.3156 J/g.K = 0.3156 kJ/kg.K

 

[Bystander]

Looks reasonable.