Calculating Speed and Acceleration of Second Hand on Town Clock

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Homework Help Overview

The discussion revolves around calculating the speed and centripetal acceleration of the tip of the second hand on a town clock, given the speed of the minute hand. The problem involves concepts from circular motion and requires understanding of angular velocity and radius.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the speed of the second hand and the minute hand, questioning the time period for one revolution. There are attempts to derive the radius using the speed and time period, and discussions about the correct application of formulas for centripetal acceleration.

Discussion Status

Some participants have provided insights into the calculations and the need for clarity in the steps taken to derive values. There is acknowledgment of errors in the calculations, but no consensus on the correct approach has been reached yet.

Contextual Notes

Participants note the lack of given radius and the implications of using different time periods for the hands of the clock. There is an emphasis on the need to show work for clarity in understanding the problem.

Muneerah
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Homework Statement



The speed of the tip of the minute hand on a
town clock is 0.00182 m/s.
What is the speed of the tip of the second
hand of the same length?
Answer in units of m/s.

What is the centripetal acceleration of the tip
of the second hand?
Answer in units of m/s2.

Homework Equations


ac=4pi2r/T2

The Attempt at a Solution


Ok to find the speed of the second, I multiplied by 60 and got .1092 m/s
for the acceleration I'm not given r, so I need to find r using this equation, V=2pi r/T
I was wondering what id T ? is it 60 seconds ? Thank you
 
Last edited:
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Muneerah said:
for the acceleration I'm not given r, so I need to find r using this equation, V=2pi r/T
I was wondering what id T ? is it 60 seconds ? Thank you

V=2pi*r/T is just distance divided by time, so T has to be the time taken for the hand to make one revolution. Of course, that depends on which hand you're considering.
 
You can find r by using the angular velocity ω from v = ω r. What is ω for the second hand?
 
so I found r which is 1.638m and I used 60s for T
I got .00728 for the acceleration and this isn't the right answer, please tell me what is it that I'm not doing right thanks.
 
If you don't show exactly how you got these numbers for the radius and for the acceleration, we cannot tell you what you are not doing right.
 
kuruman said:
If you don't show exactly how you got these numbers for the radius and for the acceleration, we cannot tell you what you are not doing right.

I'm sorry, but it's ok I figured out what I was doing wrong.
 

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