Calculating Speed of Golf Ball After Contact

In summary, the conversation discusses the calculation of the speed of a golf ball after contact, given its mass, average force, and time interval. The formula Ft=mv is used, resulting in a speed of 55.6 m/s. The conversation also mentions the possibility of air resistance being neglected and the assumption of a level course.
  • #1
15
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Homework Statement



i hit a golf ball of mass 0.045kg with an avg. Force of 2.5x10^3 N over a short time interval of 1.0 x 10^-3 s at an angle of 30 degrees with respect to the horizontal. neglect air resistance and assume a level course.

What is the speed of the ball immediately after contact?


Homework Equations



Ft=mv


The Attempt at a Solution




v=Ft/m

2500x.001/.045

v=55.6m/s?

If that is the wrong answer why? If that is right can someone further explain it to me?
 
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  • #2
jinman said:

Homework Statement



i hit a golf ball of mass 0.045kg with an avg. Force of 2.5x10^3 N over a short time interval of 1.0 x 10^-3 s at an angle of 30 degrees with respect to the horizontal. neglect air resistance and assume a level course.

What is the speed of the ball immediately after contact?


Homework Equations



Ft=mv


The Attempt at a Solution




v=Ft/m

2500x.001/.045

v=55.6m/s?

If that is the wrong answer why? If that is right can someone further explain it to me?
It looks fine to me. What do you need explaining?
 
  • #3
why would you think it's wrong?
 
  • #4
Hrmmm. I thought it would be Harder. Thank you!
 
  • #5
jinman said:
Hrmmm. I thought it would be Harder. Thank you!
No problem :smile:

Don't forget to mark the thread as 'solved' when you're done.
 

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