Calculating Speed of Golf Ball After Contact

• jinman
In summary, the conversation discusses the calculation of the speed of a golf ball after contact, given its mass, average force, and time interval. The formula Ft=mv is used, resulting in a speed of 55.6 m/s. The conversation also mentions the possibility of air resistance being neglected and the assumption of a level course.

Homework Statement

i hit a golf ball of mass 0.045kg with an avg. Force of 2.5x10^3 N over a short time interval of 1.0 x 10^-3 s at an angle of 30 degrees with respect to the horizontal. neglect air resistance and assume a level course.

What is the speed of the ball immediately after contact?

Ft=mv

The Attempt at a Solution

v=Ft/m

2500x.001/.045

v=55.6m/s?

If that is the wrong answer why? If that is right can someone further explain it to me?

jinman said:

Homework Statement

i hit a golf ball of mass 0.045kg with an avg. Force of 2.5x10^3 N over a short time interval of 1.0 x 10^-3 s at an angle of 30 degrees with respect to the horizontal. neglect air resistance and assume a level course.

What is the speed of the ball immediately after contact?

Ft=mv

The Attempt at a Solution

v=Ft/m

2500x.001/.045

v=55.6m/s?

If that is the wrong answer why? If that is right can someone further explain it to me?
It looks fine to me. What do you need explaining?

why would you think it's wrong?

Hrmmm. I thought it would be Harder. Thank you!

jinman said:
Hrmmm. I thought it would be Harder. Thank you!
No problem

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