Calculating Standing Wave Nodes: Loudspeaker Distance and Frequency

[pconstantino]

Hello All, I have been trying to solve the following exercise but I can't get my head around it:

Two loudspeakers are 24m apart and they produce sound at a frequency of 1000Hz, assume speed of sound is 330m/s, what is the distance between each node?


I don't undertand it, should I imagine the waves supperpose and therefore the distance between the nodes is half a wave lenght?

I thank you in advance.

 

[ashishsinghal]

yeah!

 

[pconstantino]

why does the problem tell me the distance of 24m then if I don't use it? that's the dilemma

 

[ashishsinghal]

maybe it is for you to check if the data obtained is correct.
nv/2l= f
if n is valid (natural number)then the data is consistent

 

[pconstantino]

i don't understand your formula mate, could you explain it please?

 

[ashishsinghal]

but it is not a natural number. Sorry, since data is inconsistent, I do not know what to expect from the question.

 

[pconstantino]

i don't get it either... someone please help me?

 

[ashishsinghal]

the formula stands for the frequencies at which standing waves are produced when both the ends are either open or closed. n is a natural number, v is velocity of sound in the medium, l is the length and f is the frequency. You can have different number of nodes and antinodes in the same medium of same length by changing frequencies. This is what n stands for. Make a diagram and check it yourself.