Calculating Stress/Deflection in Cantilever Beam

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SUMMARY

The discussion focuses on calculating stress and deflection in a cantilever beam subjected to uniform shear stress T on its upper surface. The key formula used is EI \frac{d^{3} \nu}{dx^{3}} = V, where V represents the vertical shear on a cross-section, and ν denotes the deflection. The analysis confirms that the cross-section affects the moment of inertia (I) but does not complicate the calculation process. It is established that the maximum tensile stress occurs at the fixed end of the beam, while the bending moment primarily contributes to significant deflection, with shear and torsional moments often being negligible.

PREREQUISITES
  • Understanding of cantilever beam mechanics
  • Familiarity with shear stress and bending moment concepts
  • Knowledge of moment of inertia (I) calculations
  • Basic principles of structural analysis
NEXT STEPS
  • Study the derivation of the EI \frac{d^{3} \nu}{dx^{3}} = V equation
  • Explore the effects of varying cross-sectional shapes on moment of inertia
  • Learn about shear and bending stress distribution in beams
  • Investigate real-world applications of cantilever beam analysis in engineering
USEFUL FOR

Structural engineers, mechanical engineers, and students studying mechanics of materials will benefit from this discussion, particularly those involved in beam design and analysis.

dilberg
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A cantilever beam is loaded by a uniform shear stress T on its upper surface. How to calculate the stress and deflections at the end of the beam?
 
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You can use EI \frac{d^{3} \nu}{dx^{3}} = V as long as the cross section of the beam is constant. Where \nu is the deflection.
 
In this formula V is the vertical shear on a cross section. Applied shear (T) is horizontal on the upper surface. Why should they be equal?
 
Hello, it depends on the cross section of your beam. Could you tell us which profile you are using? is it a composite beam?
 
Rectangular cross-section. The crossection will only affect I, in the formula. We can just keep it as I, so we don't have to worry about the cross-section.
 
The shear stress would induce a tensile stress in the beam with maximum tensile stress at the fixed end and only shear at the free end. Since the shear load is only on the upper surface, it is unbalanced, so it would induce a bending moment in the beam.
 
you can take a uniform force.. find the center of it. and just put in the Fr for it.. and that makes calculations simple.
 
To make sure I understand what you have; a constant rectangular cross section with a uniform horizontal force applied only along the top surface of the section and perpendiular to the longitudinal axis of the beam, and the beam has one end fixed and one end free.

Your deflection can be broken into components of that induced by horizontal shear, bending moment and torsional moment. The shear and bending moment would give translational displacements and the torsional moment generates rotational displacement about the long. axis of the beam. Usually, the bending moment will give the significant deflection of a real world beam and the shear and torsional deflection are often minimal in comparison and sometimes ignored. But you certainly cannot ignore the stresses which they produce.

The stresses will be from the direct shear, torsional shearing, and tension and compression from the bending moment. Your highest stresses will be at the fixed end.
 

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