Calculating temperature given altitude

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SUMMARY

This discussion focuses on calculating temperature at various altitudes within the troposphere using the ideal gas law and the barometric equation. The key equation derived is P1/P2 = V1/V2 * T1/T2, which simplifies the calculation by eliminating constants such as the number of moles of gas and the ideal gas constant. The ICAO Standard atmosphere suggests a temperature decrease of 0.0065 °C/m up to 11 km altitude, acknowledging that local atmospheric conditions may affect this calculation.

PREREQUISITES
  • Understanding of the ideal gas law (PV=nRT)
  • Familiarity with the barometric equation (p= p0 exp (–h/A))
  • Knowledge of basic geometry related to spheres (volume and surface area)
  • Concept of the ICAO Standard atmosphere
NEXT STEPS
  • Research the ICAO Standard atmosphere for detailed temperature and pressure profiles
  • Explore the barometric equation and its applications in meteorology
  • Learn about the impact of local atmospheric conditions on temperature calculations
  • Study advanced thermodynamics related to gas behavior at varying altitudes
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Meteorology students, atmospheric scientists, and anyone interested in understanding temperature variations with altitude in the troposphere.

moonman239
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Homework Statement


I am trying to figure out how to calculate the temperature at any given altitude in the troposphere.

Homework Equations


Let P=air pressure, V=volume of air above a given altitude, n=number of moles of gas, R=the ideal gas constant, T=temperature, and h=height above sea levelX1 and X2 = the value of X at geographic point 1 and point 2.

PV=nRT (the ideal gas law)
Volume of a sphere = 4/3*pi*radius3
Surface area of a sphere = 4*pi*radius2

The Attempt at a Solution


P1/ P2 = V1nRT1 / V2nRT2.

Now, we don't need to know what n and R are, because they are canceled out of the equation. So ignore them. We are now left with P1/P2 = V1/V2 * T1/T2.

V = 4/3*pi*radius of troposphere - (4/3 * pi * (6371.5+h))
V1 / V2 is pretty obvious and can't be simplified.
 
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The main problem that I see with this is that fall off in pressure is governed more by the barometric equation p= p0 exp (–h/A) where A is roughly 7 km, than by an increase in available volume at greater height.

I do not know how meteorologists do this calculation, but the recommendation of the ICAO Standard atmosphere is that the temperature will fall at a constant rate of 0.0065 °C/m up to 11 km altitude in the temperate zone. Obviously that is an "other things being equal" calculation that cannot take account of local atmospheric conditions.
 

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