Calculating Temperature Rise of Air in Bicycle Pump

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Homework Help Overview

The discussion revolves around calculating the temperature rise of air in a bicycle pump when compressed adiabatically. The problem involves understanding the properties of gases under compression and the relevant equations governing such processes.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial and final volumes of air in the pump and the implications of an adiabatic process. Questions are raised about the appropriate value of gamma for air and its relevance to the calculations. There is also mention of relationships involving volume, temperature, and specific heat ratio for isentropic processes.

Discussion Status

The conversation is ongoing, with participants exploring different aspects of the problem, including the nature of the process and the equations that may apply. Some guidance has been offered regarding the specific heat ratio and the assumption of ideal gas behavior, but no consensus has been reached on the approach to take.

Contextual Notes

Participants note that isentropic processes have not been covered in their coursework yet, which may affect their understanding of the problem. There is also a focus on the assumptions made regarding the behavior of air under compression.

yossup
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Homework Statement



A bicycle pump is a cylinder 20cm long and 3.0cm in diameter. The pump contains air at 21.0C and 1.0atm. If the outlet at the base of the pump is blocked and the handle is pushed in very quickly, compressing the air to half its original volume, how hot does the air in the pump become?

Homework Equations



PV=nRT
PV^gamma = PV^gamma

The Attempt at a Solution



So the intial volume is 1.55m^3. The final volume is .775m^3. And because the handle is pushed very quickly, the process is adiabatic. So I want to know what gamma is but do I use the one for di or triatomic? Then i just use the W = integral P dv?
 
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yossup said:

Homework Statement



A bicycle pump is a cylinder 20cm long and 3.0cm in diameter. The pump contains air at 21.0C and 1.0atm. If the outlet at the base of the pump is blocked and the handle is pushed in very quickly, compressing the air to half its original volume, how hot does the air in the pump become?

Homework Equations



PV=nRT
PV^gamma = PV^gamma

The Attempt at a Solution



So the intial volume is 1.55m^3. The final volume is .775m^3. And because the handle is pushed very quickly, the process is adiabatic. So I want to know what gamma is but do I use the one for di or triatomic? Then i just use the W = integral P dv?

Air is composed mostly of Nitrogen and Oxygen (which are diatomic molecules). Thus, the specific heat ratio of air is assigned the value of 1.4.

Since the air is compressed quickly, you may assume it is adiabatic. At relatively low pressures air is also considered to behave as an ideal gas. If you further assume it is a reversible process then you end up with an isentropic process.

Do you know of any relationships that contain the volume, temperature, and specific heat ratio for an isentropic process?

CS
 
Um...we haven't even gone over isentropic processes yet but is the equation your're talking about this? PdV + VdP = nRdT
 
yossup said:
Um...we haven't even gone over isentropic processes yet but is the equation your're talking about this? PdV + VdP = nRdT

T_2 = T_1 \cdot \left(\frac{V_1}{V_2}\right)^{k-1}

where k is the specific heat ratio.

CS
 

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