Calculating temperature with energy absorbed

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Homework Help Overview

The problem involves calculating the temperature increase of two pitchers made of different materials (copper and glass) after absorbing energy from sunlight over a specified time period. The context is set within thermodynamics, specifically focusing on heat transfer and specific heat capacity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the energy absorbed by the pitchers over different time intervals and question how to calculate the total energy absorbed in one hour. There is an exploration of rearranging the heat transfer equation to solve for temperature.

Discussion Status

Some participants have provided calculations related to the energy absorbed over one hour and have suggested using this value in the heat transfer equation. There is an ongoing exploration of the specific heat capacities for both materials and how they affect the temperature change.

Contextual Notes

Participants are working under the assumption that the specific heat capacities for copper and glass are known and are discussing the implications of these values on the temperature increase. There is also a focus on the conversion of mass from grams to kilograms for calculations.

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Homework Statement



Two pitchers of lemonade are left sitting in the sun at a picnic. One pitcher is made of copper and the other of glass. If each empty pitcher has a mass of 965 g and absorbs 1.0 x 10^3 J of energy 10.0 minutes, calculate the temperature increase of both empty pitchers in 1.0 hours.

Homework Equations



Q=mcΔT

The Attempt at a Solution



I still have no idea.
I tried rearranging the equations... and turning it into seconds...
My book says the answer for copper is 16°C and glass is 7.4°C.

Homework Statement


 
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If the pitchers absorb 1000J of energy in 10 minutes, how much energy will they absorb in 1 hour?
 
Xisune said:
If the pitchers absorb 1000J of energy in 10 minutes, how much energy will they absorb in 1 hour?

1000J in 10 minutes
60/10 = 6
∴ 6 x 1000 = 6000J in one hour?
 
Yes, now use that value for Q.
 
Xisune said:
Yes, now use that value for Q.

but isn't Q already 6000J/h? i am looking for temperature which is T.. so should i rearrange fore T= Q/mc ?

Q= heat or energy absorbed (J) = 6000J/h
m= mass (kg) = 0.965kg
c= specific heat capacity(J/(kg°C) ) = for copper: 3.8 x 10^2 and for glass: 8.4 x 10^2


right?
 
YAY! from that, I got it. Thank you! :)
 

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