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Calculating temperature with energy absorbed

  1. Jun 25, 2012 #1
    1. The problem statement, all variables and given/known data

    Two pitchers of lemonade are left sitting in the sun at a picnic. One pitcher is made of copper and the other of glass. If each empty pitcher has a mass of 965 g and absorbs 1.0 x 10^3 J of energy 10.0 minutes, calculate the temperature increase of both empty pitchers in 1.0 hours.

    2. Relevant equations

    Q=mcΔT

    3. The attempt at a solution

    I still have no idea.
    I tried rearranging the equations... and turning it into seconds...
    My book says the answer for copper is 16°C and glass is 7.4°C.
    1. The problem statement, all variables and given/known data
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Jun 25, 2012 #2
    If the pitchers absorb 1000J of energy in 10 minutes, how much energy will they absorb in 1 hour?
     
  4. Jun 25, 2012 #3
    1000J in 10 minutes
    60/10 = 6
    ∴ 6 x 1000 = 6000J in one hour?
     
  5. Jun 25, 2012 #4
    Yes, now use that value for Q.
     
  6. Jun 25, 2012 #5
    but isn't Q already 6000J/h? i am looking for temperature which is T.. so should i rearrange fore T= Q/mc ?

    Q= heat or energy absorbed (J) = 6000J/h
    m= mass (kg) = 0.965kg
    c= specific heat capacity(J/(kg°C) ) = for copper: 3.8 x 10^2 and for glass: 8.4 x 10^2


    right?
     
  7. Jun 25, 2012 #6
    YAY! from that, I got it. Thank you! :)
     
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