# Calculating temperature with energy absorbed

1. Jun 25, 2012

### pamelajanas

1. The problem statement, all variables and given/known data

Two pitchers of lemonade are left sitting in the sun at a picnic. One pitcher is made of copper and the other of glass. If each empty pitcher has a mass of 965 g and absorbs 1.0 x 10^3 J of energy 10.0 minutes, calculate the temperature increase of both empty pitchers in 1.0 hours.

2. Relevant equations

Q=mcΔT

3. The attempt at a solution

I still have no idea.
I tried rearranging the equations... and turning it into seconds...
My book says the answer for copper is 16°C and glass is 7.4°C.
1. The problem statement, all variables and given/known data
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jun 25, 2012

### Xisune

If the pitchers absorb 1000J of energy in 10 minutes, how much energy will they absorb in 1 hour?

3. Jun 25, 2012

### pamelajanas

1000J in 10 minutes
60/10 = 6
∴ 6 x 1000 = 6000J in one hour?

4. Jun 25, 2012

### Xisune

Yes, now use that value for Q.

5. Jun 25, 2012

### pamelajanas

but isn't Q already 6000J/h? i am looking for temperature which is T.. so should i rearrange fore T= Q/mc ?

Q= heat or energy absorbed (J) = 6000J/h
m= mass (kg) = 0.965kg
c= specific heat capacity(J/(kg°C) ) = for copper: 3.8 x 10^2 and for glass: 8.4 x 10^2

right?

6. Jun 25, 2012

### pamelajanas

YAY! from that, I got it. Thank you! :)