Calculating the Accepted Value of g with a Pendulum

[Mitchtwitchita]

Homework Statement

Find the accepted value of g

Homework Equations

(sigma)(g) = |g|[(sigma(L))/|L| + 2 (sigma(T))/|T|]
Acceleration due to gravity for a pendulum broken down.

The Attempt at a Solution

I really do not have a clue. If I had to guess, I would say 2. Can anybody please offer me some help with this problem?

 

[Astronuc]

Please write the expression for g in terms of L and T?

Then write the expression for the error of g, or σ_g, or better σ_g².

Is one given the errors (σ) of measurement?

 

[Mitchtwitchita]

Would it be...

sigma g/g = sqr[((sigma L)/L)^2 + 2((sigma T)/T)^2]

gbest = (4pi)^2 x L/T^2

The first one would give the errors of measurement?

 

[Astronuc]

sigma g/g = sqr[((sigma L)/L)^2 + 2((sigma T)/T)^2]

Is this the formula that one is given?

If so, the what is the expression of g in terms of the other variables?

 

[Mitchtwitchita]

O.k. I totally confused...let's start from the beginning. The original equation was:

g = 4(pi^2)L/T^2, then, to the best of my knowledge I'm supposed to break down the equation to:

g = 4(pi)^2LT^-2, and this is where I get confused because I've never dealt with something like this before, and I wasn't given much instruction. i also appreciate you being patient with me.

So, after this I assume I'm supposed to break down the equation into an error equation:

sigma g/g = sigma (4)/|4| + 2(sigma (pi)/|pi|) + sigma (L)/|L| + |-2|(sigma (T)/|T|)

Now, I get this equation from an example but I get confused on what to do with it after this point. I know 4 and pi are constants and can be removed from the equation but I don't really know where to take it from here.