Calculating the Diameter of the Moon's Virtual Image

[elitespart]

1. The radius of Earth is 6.40 x 10³ km. The moon is about 3.84 x 10^5 km away from Earth and has a diameter of 3475 km. The Pacific Ocean surface, which can be considered a convex mirror, forms a virtual image of the moon. What is the diameter of that image?

2. 1/p + 1/q = 1/f

M = h'/h = -q/p

3. Ok. So since the image is virtual, q (image distance) is negative. p (object distance) is 3.84 x 10^5 km and h(object height) is 3475 m. Could the radius of Earth be used as the radius of curvature? I'm confused as to how to set up the equations in order to get the diameter of the image(h')

 

[G01]

Yes, use the radius of the Earth as the radius of the mirror formed by the pacific ocean. Think of the water covered part of the Earth as a giant, convex, spherical mirror.

HINT: Can you find the focal length of the ocean from what you know?

 

[elitespart]

Ok. yeah that clears stuff up because I can get focal length from the radius. Thanks.

 

[elitespart]

I'm getting like 28.7 km for an answer. Can anyone confirm?