Calculating the Distance Dropped by a Baseball Thrown at 116 km/h

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SUMMARY

A baseball thrown horizontally at 116 km/h (32.22 m/s) will drop due to gravity as it travels 18.4 meters to home plate. The time taken for the ball to reach home plate is calculated as 0.57 seconds. Using the formula for vertical displacement under constant acceleration, the distance dropped can be determined using the equation \(\Delta y = \frac{1}{2} g t^2\), where \(g = 9.81 m/s^2\). This results in a drop of approximately 1.6 meters by the time the ball reaches home plate.

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a) A pitcher throws a baseball horizontally at 116 km/h toward home plate, which is 18.4 m away. How far will the ball drop due to gravity by the time it reaches home plate?

g=9.81m/s^2
v=116km/h


i tried to solve this question, but i don't know where to get the high.
116km/h=32.22m/s
18.4/32.22=0.57s
`````

please help me, thank you! i am so confuse with the question it actually ask.
 
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Basically, the question that it is asking is that it wants you to find how far the ball dropped since it left the pitcher's hand. What I did was that i wrote out all my horizontal givens and my vertical givens and I just solved for \Deltay after I got all the other information.
 

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