Calculating the Distance of a Sonar Echo

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The sonar echo returns to a submarine after 1.10 seconds, and the speed of sound underwater is given as 1533 m/s. To find the distance to the object, the calculation involves using the formula distance = rate x time, divided by two since the echo travels to the object and back. The calculated distance is approximately 744.165 meters, but significant figures indicate the answer should be rounded to three digits. Additional factors like depth, temperature, and salinity could affect accuracy in real-world scenarios, but they are not required for this problem.
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Homework Statement


A sonar echo returns to a submarine 1.10s after being emitted. What is the distance to the object creating the echo?


Homework Equations



rate X time = distance

The Attempt at a Solution

( 1533m/s X 1.01s) divided by 2 = distance
 
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It looks like you're on the right track. What answer did you get?

So what is your question?
 
The answer I came up with 744.165m
 
I take it the 1533 m/s is the speed of sound under water ? If so, you should mention it under 'given/known' data. That prevents we have to guess after what you were given to do the exercise.

As a physicist, I would say that the 1.10 s has three significant digits at most. So the answer shouldn't have more than 3 digits, (max 4 if the first is a 1).
 
BvU said:
I take it the 1533 m/s is the speed of sound under water ? If so, you should mention it under 'given/known' data. That prevents we have to guess after what you were given to do the exercise.

As a physicist, I would say that the 1.10 s has three significant digits at most. So the answer shouldn't have more than 3 digits, (max 4 if the first is a 1).

To be even more accurate in the real world, you'd need to specify the depth, the temperate and salinity too but that's beyond the scope of this problem.

http://en.wikipedia.org/wiki/Underwater_acoustics
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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