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Calculating The Fermi Energy - Condensed Matter Physics
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[QUOTE="12x4, post: 4997253, member: 537748"] [h2]Homework Statement [/h2] Calculate the Fermi energy, E[SUB]F[/SUB] at 0K for potassium (atomic weight = 39, density = 860 kgm3). [h2]Homework Equations[/h2] K[SUB]F[/SUB][SUP]3[/SUP] = 3π[SUP]2[/SUP]n Fermi Momentum ρ = h(bar)K[SUB]F[/SUB] [h2]The Attempt at a Solution[/h2] :[/B] For the first part: Using: E = ρ[SUP]2[/SUP]/ 2m Can substitute Fermi momentum into that to get: E[SUB]F[/SUB] = h(bar)[SUP]2[/SUP] K[SUB]F[/SUB][SUP]2[/SUP] / 2m K[SUB]F[/SUB][SUP]2[/SUP] = √(3π[SUP]2[/SUP]n) = π√(3n) Putting all the together I got: E[SUB]F[/SUB] = h(bar)[SUP]2[/SUP] π √(3n) / 2m which is the same as: E[SUB]F[/SUB] = h[SUP]2[/SUP] √(3n) / 4m I'm not too sure what to do after this point as I'm not sure how the atomic weight or density can give me a value for n and m. I do have written in my notes that n = N/v but again I wasn't sure how this would help me. I feel like I must be going down the wrong path to come out with an equation that needs completely different things to what the question is providing me with. But honestly I have just started this condensed matter course and haven't really got my feet yet.Thanks in advance to anyone that replies. [B][/B] [/QUOTE]
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Calculating The Fermi Energy - Condensed Matter Physics
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